Can You Answer This Senior-Level JavaScript Promise Interview Question

Can You Answer This Senior-Level JavaScript Promise Interview Question?

JavaScript developers know that understanding the inner workings of Promises is essential, especially when it comes to handling asynchronous code effectively. Mastering Promises can make the difference between writing efficient, non-blocking code and code that’s riddled with bugs and difficult to maintain. In senior-level interviews, you’re likely to encounter questions designed to probe your understanding of the JavaScript event loop and microtasks. Let’s look at a complex Promise-based question similar to the one in the example above and break it down step-by-step to understand how it executes.

				
					const promise = new Promise((resolve, reject) => {
  console.log("a");
  setTimeout(() => {
    console.log("timeout");
    resolve("resolved");
    console.log("end timeout");
  }, 0);
  console.log("b");
});

promise.then((result) => {
  console.log(result);
});

console.log("c");

				
			

Understanding the Code Step-by-Step

Let’s break down this code line by line and see what’s happening under the hood:

1. Promise Instantiation

The Promise is created with the following code:

				
					const promise = new Promise((resolve, reject) => {
  console.log("a");
  // ...
  console.log("b");
});

				
			

Creating a Promise immediately executes the function provided to its constructor. This is a synchronous operation, meaning the code inside the Promise runs right away, before any asynchronous code such as setTimeout or then.

Console Output at this Stage:

  • console.log("a"); logs a
  • console.log("b"); logs b

So, so far, the output is:

				
					a
b

				
			

2. The setTimeout Function

				
					setTimeout(() => {
  console.log("timeout");
  resolve("resolved");
  console.log("end timeout");
}, 0);

				
			

This setTimeout callback is pushed to the macrotask queue (or the “task queue”), which executes after the main thread has finished processing all synchronous code. Since the timer delay is set to 0, the callback will be placed on the macrotask queue and executed as soon as possible after the main thread is done.

Notice that this section of code has two console.log statements:

  • console.log("timeout"); (will log timeout)
  • console.log("end timeout"); (will log end timeout after resolving the Promise)

Key Point: The resolve("resolved") statement doesn’t cause the callback passed to then to run immediately. It simply moves the Promise’s then callback to the microtask queue, which gets priority over the macrotask queue once the main script finishes executing.

3. Attaching then

				
					promise.then((result) => {
  console.log(result);
});

				
			

When we attach a then to a Promise, the callback provided to then will run asynchronously after the Promise is resolved. However, it’s added to the microtask queue, which executes immediately after the current call stack is empty but before any macrotask.

4. Logging c

				
					console.log("c");

				
			

This line executes immediately after the Promise and setTimeout setup because it’s outside any asynchronous code.

At this point, the output log is:

				
					a
b
c

				
			

The Event Loop

When the main code finishes running, the event loop checks the microtask queue before moving to the macrotask queue. Here’s the sequence the event loop follows in our example:

  1. The main script (a, b, c) executes first.
  2. The microtask queue is checked next, but it’s empty at this point because the Promise hasn’t been resolved yet.
  3. The macrotask queue is checked and executes setTimeout’s callback:
    • Logs timeout
    • Resolves the Promise with "resolved", pushing the then callback to the microtask queue
    • Logs end timeout
  4. The event loop finishes the current macrotask (setTimeout) and goes back to the microtask queue.
    • Executes console.log(result) with "resolved" as the argument.

Final Output and Order

Putting it all together, here’s the full order of output:

				
					a
b
c
timeout
end timeout
resolved

				
			

Key Takeaways from This Code

  1. Promises are synchronous by default: Code inside a Promise executor function runs immediately.
  2. Microtasks vs. Macrotasks: Microtasks (like Promise.then) take precedence over macrotasks (like setTimeout), so they will execute as soon as the main script completes.
  3. The Event Loop: It’s essential to understand the event loop in JavaScript to predict the order of output accurately. The event loop first empties the call stack, then processes the microtask queue, and finally moves to the macrotask queue.

Practice Questions

To solidify your understanding, try answering these similar questions and follow the logic above to predict their outputs:

Question 1

				
					const promise = new Promise((resolve) => {
  console.log("x");
  resolve("y");
});

promise.then((res) => {
  console.log(res);
});

console.log("z");

				
			

Question 2

				
					console.log("start");

setTimeout(() => {
  console.log("setTimeout");
}, 0);

Promise.resolve().then(() => {
  console.log("promise1");
}).then(() => {
  console.log("promise2");
});

console.log("end");

				
			

Working through these examples will deepen your understanding of how JavaScript handles asynchronous operations with Promises and the event loop. Senior-level questions often focus on these subtleties, so knowing this well could make a big difference in your interview performance!

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